Sucrose Solution Preparation

How many grams of sucrose to weigh for any molarity and volume, with a full recipe table.

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To prepare a solution of sucrose you need the grams, and grams is molarity × volume in litres × 342.297 g/mol. A litre of 1 M takes 342.297 g; 500 mL of 0.1 M takes 17.115 g; 250 mL of 0.01 M takes 855.74 mg. Enter the strength you want and the volume you want it in, and the calculator returns the mass to weigh together with the same figure in milligrams and as a percentage strength.

The figure comes from the formula. Sucrose is 12 × 12.011 (C) + 22 × 1.008 (H) + 11 × 15.999 (O), which is 342.297 g/mol, taking standard atomic weights, and every page here computes that sum rather than quoting it. Oxygen makes up the largest share of the mass: 11 of the 45 atoms in a formula unit are oxygen, and they account for 175.989 g of the 342.297 g, or 51.41% by mass. The derivation table below breaks the whole molecule down element by element.

Order of operations matters more than precision here. Dissolve the solid in rather less than the final volume, then make up to the mark once it has all gone into solution and come back to room temperature — warm solutions read low when they cool. If the calculated mass is under about 20 mg, prepare ten times the strength and dilute it tenfold by pipette instead, because C₁V₁ = C₂V₂ carries less error than a marginal weighing.

Table sugar, a disaccharide of glucose and fructose. Sugar solutions are quoted in degrees Brix, which is percent by weight rather than molarity. At 342.297 g/mol it is heavier than 19 of the 21 organic compounds covered here, and that ranking matters more than it looks: EDTA has a molar mass of 292.244 g/mol, so a gram of it contains 17.1% more formula units than a gram of sucrose. Weigh by mass and you are not weighing equal amounts of substance.

Two practical things move the result. Purity below 100% means the weighed mass overstates how much compound you have — at 98% assay, 6.8459 g of every 342.297 g is not the compound — and any water picked up from the air does the same. Both are systematic, so they shift every solution made from that jar in the same direction.

The formula

m = c × (V ÷ 1000) × 342.297
c
The molarity you want, in mol/L
V
The volume you want to make, in millilitres
342.297
The molar mass of sucrose in g/mol, derived from its formula
m
The mass of sucrose to weigh out, in grams

How it works, step by step

  1. Enter the molarity you want, in mol/L.
  2. Enter the volume you want to make, in millilitres.
  3. The two are multiplied together and by 342.297 g/mol.
  4. The result is the mass to weigh; dissolve it in part of the volume and then make up to the mark.

Worked examples

250 mL of 0.1 M sucrose

Weigh 8.55743 g. That is 0.1 M × 0.25 L × 342.297 g/mol, and it comes to 8557.43 mg if your balance is set to milligrams. Dissolve in about 175 mL first, then make up to 250 mL.

500 mL of 0.5 M sucrose

Weigh 85.5743 g. That is 0.5 M × 0.5 L × 342.297 g/mol, and it comes to 85,574.2 mg if your balance is set to milligrams. Dissolve in about 350 mL first, then make up to 500 mL.

1000 mL of 1 M sucrose

Weigh 342.297 g. That is 1 M × 1 L × 342.297 g/mol, and it comes to 342,297 mg if your balance is set to milligrams. Dissolve in about 700 mL first, then make up to 1000 mL.

How to read your score

0–0NothingNothing to weigh.
0–0.05Below a sensible weighingUnder 50 mg. Weigh ten or a hundred times this and dilute; the balance error does not shrink with the sample.
0.05–10Weighable directlyFrom 50 mg to 10 g, which is where a two- or three-decimal balance gives better than 1% on the mass.
10–—Large batchMore than 10 g of sucrose. Worth checking solubility and, for a solid that generates heat on dissolving, adding it in portions.

Frequently asked questions

What is the molar mass of sucrose (C12H22O11)?

It is 342.297 g/mol. That is the sum of the standard atomic weights of every atom in the formula: 12 × 12.011 (C) + 22 × 1.008 (H) + 11 × 15.999 (O). One mole of sucrose therefore weighs 342.297 g, and a gram of it is 2.9214 mmol.

What percentage of sucrose is oxygen?

51.41% by mass. Each formula unit contains 11 oxygen atoms contributing 175.989 g of the 342.297 g total, so 100 g of sucrose contains 51.41 g of oxygen and a kilogram contains 514.14 g of it.

How much sucrose do I need for 1 litre of 1 M solution?

342.297 g — the molar mass in grams, which is what a 1 molar solution means. For 1 L of 0.1 M it is 34.2297 g, and for 1 L of 0.01 M it is 3.42297 g.

How much for 100 mL of 0.1 M?

3.42297 g. The volume is a tenth of a litre and the strength a tenth of molar, so the mass is a hundredth of 342.297 g. In milligrams that is 3422.97 mg.

Do I dissolve the solid first or make up the volume first?

Dissolve first, in perhaps 70% of the final volume, then make up to the mark. Adding solid to a full flask overshoots the volume and leaves the solution weak, and undissolved solid at the mark means the strength keeps changing as it goes in.

Can I dilute a stock solution instead of weighing?

Yes, and it is more accurate for small amounts. C₁V₁ = C₂V₂: to get 500 mL of 0.01 M from a 0.5 M stock, take 10 mL of stock and make up to 500 mL. Weighing the 1711.5 mg that 500 mL of 0.01 M needs directly is the harder of the two.

Solution recipes for sucrose

How the molar mass of sucrose is arrived at
ElementAtomsAtomic weightContribution (g/mol)By mass
Oxygen (O)1115.999175.98951.41%
Carbon (C)1212.011144.13242.11%
Hydrogen (H)221.00822.1766.479%
Total — one mole of sucrose342.297100%

Standard atomic weights, IUPAC 2021. The contribution column is atoms × atomic weight, and the total is the molar mass this page uses: 342.297 g/mol.

Grams of sucrose needed for a standard solution
Targetfor 100 mLfor 250 mLfor 500 mLfor 1 L
0.001 M34.2297 mg85.5743 mg171.149 mg342.297 mg
0.005 M171.149 mg427.871 mg855.743 mg1.71149 g
0.01 M342.297 mg855.743 mg1.71149 g3.42297 g
0.05 M1.71149 g4.27871 g8.55743 g17.1149 g
0.1 M3.42297 g8.55743 g17.1149 g34.2297 g
0.15 M5.13446 g12.8361 g25.6723 g51.3446 g
0.2 M6.84594 g17.1149 g34.2297 g68.4594 g
0.25 M8.55743 g21.3936 g42.7871 g85.5743 g
0.5 M17.1149 g42.7871 g85.5743 g171.149 g
1 M34.2297 g85.5743 g171.149 g342.297 g
2 M68.4594 g171.149 g342.297 g684.594 g

Each cell is molarity × volume in litres × 342.297 g/mol. Dissolve the solid first and then make up to the marked volume — adding solid to a full volume overshoots it.

Sucrose among other organic compounds, by molar mass
CompoundFormulaMolar mass (g/mol)Millimoles in 1 g
Uric acidC5H4N4O3168.1125.9484
GlucoseC6H12O6180.1565.5507
AspirinC9H8O4180.1595.5507
CaffeineC8H10N4O2194.1945.1495
EDTAC10H16N2O8292.2443.4218
Sucrose (this page)C12H22O11342.2972.9214
CholesterolC27H46O386.6642.5862

Ordered by molar mass. The last column is 1000/M, which is the number a weighed gram actually gives you.

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