Lactic acid Solution Preparation

How many grams of lactic acid to weigh for any molarity and volume, with a full recipe table.

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To prepare a solution of lactic acid you need the grams, and grams is molarity × volume in litres × 90.078 g/mol. A litre of 1 M takes 90.078 g; 500 mL of 0.1 M takes 4.5039 g; 250 mL of 0.01 M takes 225.19 mg. Enter the strength you want and the volume you want it in, and the calculator returns the mass to weigh together with the same figure in milligrams and as a percentage strength.

The figure comes from the formula. Lactic acid is 3 × 12.011 (C) + 6 × 1.008 (H) + 3 × 15.999 (O), which is 90.078 g/mol, taking standard atomic weights, and every page here computes that sum rather than quoting it. Oxygen makes up the largest share of the mass: 3 of the 12 atoms in a formula unit are oxygen, and they account for 47.997 g of the 90.078 g, or 53.28% by mass. The derivation table below breaks the whole molecule down element by element.

Order of operations matters more than precision here. Dissolve the solid in rather less than the final volume, then make up to the mark once it has all gone into solution and come back to room temperature — warm solutions read low when they cool. If the calculated mass is under about 20 mg, prepare ten times the strength and dilute it tenfold by pipette instead, because C₁V₁ = C₂V₂ carries less error than a marginal weighing.

The acid in sour milk and sourdough, and a cosmetic exfoliant. Sold as an 80 or 88% syrup rather than a solid, because it is hygroscopic. At 90.078 g/mol it is heavier than 6 of the 12 acids covered here, and that ranking matters more than it looks: oxalic acid has a molar mass of 90.034 g/mol, so a gram of it contains 0.0489% more formula units than a gram of lactic acid. Weigh by mass and you are not weighing equal amounts of substance.

One more step applies if you are starting from a concentrated bottle. Concentrated acids are labelled as a percentage by weight together with a density, not as a molarity, so getting to mol/L means multiplying density by that percentage and dividing by 90.078 g/mol. A page like this one gives you the last of those three numbers; the first two are on the bottle, and they vary between grades.

The formula

m = c × (V ÷ 1000) × 90.078
c
The molarity you want, in mol/L
V
The volume you want to make, in millilitres
90.078
The molar mass of lactic acid in g/mol, derived from its formula
m
The mass of lactic acid to weigh out, in grams

How it works, step by step

  1. Enter the molarity you want, in mol/L.
  2. Enter the volume you want to make, in millilitres.
  3. The two are multiplied together and by 90.078 g/mol.
  4. The result is the mass to weigh; dissolve it in part of the volume and then make up to the mark.

Worked examples

250 mL of 0.1 M lactic acid

Weigh 2.25195 g. That is 0.1 M × 0.25 L × 90.078 g/mol, and it comes to 2251.95 mg if your balance is set to milligrams. Dissolve in about 175 mL first, then make up to 250 mL.

500 mL of 0.5 M lactic acid

Weigh 22.5195 g. That is 0.5 M × 0.5 L × 90.078 g/mol, and it comes to 22,519.5 mg if your balance is set to milligrams. Dissolve in about 350 mL first, then make up to 500 mL.

1000 mL of 1 M lactic acid

Weigh 90.078 g. That is 1 M × 1 L × 90.078 g/mol, and it comes to 90,078 mg if your balance is set to milligrams. Dissolve in about 700 mL first, then make up to 1000 mL.

How to read your score

0–0NothingNothing to weigh.
0–0.05Below a sensible weighingUnder 50 mg. Weigh ten or a hundred times this and dilute; the balance error does not shrink with the sample.
0.05–10Weighable directlyFrom 50 mg to 10 g, which is where a two- or three-decimal balance gives better than 1% on the mass.
10–—Large batchMore than 10 g of lactic acid. Worth checking solubility and, for a solid that generates heat on dissolving, adding it in portions.

Frequently asked questions

What is the molar mass of lactic acid (C3H6O3)?

It is 90.078 g/mol. That is the sum of the standard atomic weights of every atom in the formula: 3 × 12.011 (C) + 6 × 1.008 (H) + 3 × 15.999 (O). One mole of lactic acid therefore weighs 90.078 g, and a gram of it is 11.101 mmol.

What percentage of lactic acid is oxygen?

53.28% by mass. Each formula unit contains 3 oxygen atoms contributing 47.997 g of the 90.078 g total, so 100 g of lactic acid contains 53.28 g of oxygen and a kilogram contains 532.84 g of it.

How much lactic acid do I need for 1 litre of 1 M solution?

90.078 g — the molar mass in grams, which is what a 1 molar solution means. For 1 L of 0.1 M it is 9.0078 g, and for 1 L of 0.01 M it is 0.90078 g.

How much for 100 mL of 0.1 M?

0.90078 g. The volume is a tenth of a litre and the strength a tenth of molar, so the mass is a hundredth of 90.078 g. In milligrams that is 900.78 mg.

Do I dissolve the solid first or make up the volume first?

Dissolve first, in perhaps 70% of the final volume, then make up to the mark. Adding solid to a full flask overshoots the volume and leaves the solution weak, and undissolved solid at the mark means the strength keeps changing as it goes in.

Can I dilute a stock solution instead of weighing?

Yes, and it is more accurate for small amounts. C₁V₁ = C₂V₂: to get 500 mL of 0.01 M from a 0.5 M stock, take 10 mL of stock and make up to 500 mL. Weighing the 450.39 mg that 500 mL of 0.01 M needs directly is the harder of the two.

Solution recipes for lactic acid

How the molar mass of lactic acid is arrived at
ElementAtomsAtomic weightContribution (g/mol)By mass
Oxygen (O)315.99947.99753.28%
Carbon (C)312.01136.03340%
Hydrogen (H)61.0086.0486.714%
Total — one mole of lactic acid90.078100%

Standard atomic weights, IUPAC 2021. The contribution column is atoms × atomic weight, and the total is the molar mass this page uses: 90.078 g/mol.

Grams of lactic acid needed for a standard solution
Targetfor 100 mLfor 250 mLfor 500 mLfor 1 L
0.001 M9.0078 mg22.5195 mg45.039 mg90.078 mg
0.005 M45.039 mg112.597 mg225.195 mg450.39 mg
0.01 M90.078 mg225.195 mg450.39 mg900.78 mg
0.05 M450.39 mg1.12598 g2.25195 g4.5039 g
0.1 M900.78 mg2.25195 g4.5039 g9.0078 g
0.15 M1.35117 g3.37792 g6.75585 g13.5117 g
0.2 M1.80156 g4.5039 g9.0078 g18.0156 g
0.25 M2.25195 g5.62988 g11.2598 g22.5195 g
0.5 M4.5039 g11.2598 g22.5195 g45.039 g
1 M9.0078 g22.5195 g45.039 g90.078 g
2 M18.0156 g45.039 g90.078 g180.156 g

Each cell is molarity × volume in litres × 90.078 g/mol. Dissolve the solid first and then make up to the marked volume — adding solid to a full volume overshoots it.

Lactic acid among other acids, by molar mass
CompoundFormulaMolar mass (g/mol)Millimoles in 1 g
Boric acidH3BO361.83116.173
Nitric acidHNO363.01215.87
Oxalic acidC2H2O490.03411.107
Lactic acid (this page)C3H6O390.07811.101
Phosphoric acidH3PO497.9937610.205
Sulfuric acidH2SO498.07210.197
Tartaric acidC4H6O6150.0866.6628

Ordered by molar mass. The last column is 1000/M, which is the number a weighed gram actually gives you.

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