Glycine Solution Preparation

How many grams of glycine to weigh for any molarity and volume, with a full recipe table.

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To prepare a solution of glycine you need the grams, and grams is molarity × volume in litres × 75.067 g/mol. A litre of 1 M takes 75.067 g; 500 mL of 0.1 M takes 3.7533 g; 250 mL of 0.01 M takes 187.67 mg. Enter the strength you want and the volume you want it in, and the calculator returns the mass to weigh together with the same figure in milligrams and as a percentage strength.

The figure comes from the formula. Glycine is 2 × 12.011 (C) + 5 × 1.008 (H) + 14.007 (N) + 2 × 15.999 (O), which is 75.067 g/mol, taking standard atomic weights, and every page here computes that sum rather than quoting it. Oxygen makes up the largest share of the mass: 2 of the 10 atoms in a formula unit are oxygen, and they account for 31.998 g of the 75.067 g, or 42.63% by mass. The derivation table below breaks the whole molecule down element by element.

Order of operations matters more than precision here. Dissolve the solid in rather less than the final volume, then make up to the mark once it has all gone into solution and come back to room temperature — warm solutions read low when they cool. If the calculated mass is under about 20 mg, prepare ten times the strength and dilute it tenfold by pipette instead, because C₁V₁ = C₂V₂ carries less error than a marginal weighing.

The smallest amino acid, a buffer component in electrophoresis and a sweetener. Highly soluble and stable in solution. At 75.067 g/mol it is heavier than 6 of the 21 organic compounds covered here, and that ranking matters more than it looks: ethylene glycol has a molar mass of 62.068 g/mol, so a gram of it contains 20.9% more formula units than a gram of glycine. Weigh by mass and you are not weighing equal amounts of substance.

Two practical things move the result. Purity below 100% means the weighed mass overstates how much compound you have — at 98% assay, 1.5013 g of every 75.067 g is not the compound — and any water picked up from the air does the same. Both are systematic, so they shift every solution made from that jar in the same direction.

The formula

m = c × (V ÷ 1000) × 75.067
c
The molarity you want, in mol/L
V
The volume you want to make, in millilitres
75.067
The molar mass of glycine in g/mol, derived from its formula
m
The mass of glycine to weigh out, in grams

How it works, step by step

  1. Enter the molarity you want, in mol/L.
  2. Enter the volume you want to make, in millilitres.
  3. The two are multiplied together and by 75.067 g/mol.
  4. The result is the mass to weigh; dissolve it in part of the volume and then make up to the mark.

Worked examples

250 mL of 0.1 M glycine

Weigh 1.87667 g. That is 0.1 M × 0.25 L × 75.067 g/mol, and it comes to 1876.67 mg if your balance is set to milligrams. Dissolve in about 175 mL first, then make up to 250 mL.

500 mL of 0.5 M glycine

Weigh 18.7667 g. That is 0.5 M × 0.5 L × 75.067 g/mol, and it comes to 18,766.8 mg if your balance is set to milligrams. Dissolve in about 350 mL first, then make up to 500 mL.

1000 mL of 1 M glycine

Weigh 75.067 g. That is 1 M × 1 L × 75.067 g/mol, and it comes to 75,067 mg if your balance is set to milligrams. Dissolve in about 700 mL first, then make up to 1000 mL.

How to read your score

0–0NothingNothing to weigh.
0–0.05Below a sensible weighingUnder 50 mg. Weigh ten or a hundred times this and dilute; the balance error does not shrink with the sample.
0.05–10Weighable directlyFrom 50 mg to 10 g, which is where a two- or three-decimal balance gives better than 1% on the mass.
10–—Large batchMore than 10 g of glycine. Worth checking solubility and, for a solid that generates heat on dissolving, adding it in portions.

Frequently asked questions

What is the molar mass of glycine (C2H5NO2)?

It is 75.067 g/mol. That is the sum of the standard atomic weights of every atom in the formula: 2 × 12.011 (C) + 5 × 1.008 (H) + 14.007 (N) + 2 × 15.999 (O). One mole of glycine therefore weighs 75.067 g, and a gram of it is 13.321 mmol.

What percentage of glycine is oxygen?

42.63% by mass. Each formula unit contains 2 oxygen atoms contributing 31.998 g of the 75.067 g total, so 100 g of glycine contains 42.63 g of oxygen and a kilogram contains 426.26 g of it.

How much glycine do I need for 1 litre of 1 M solution?

75.067 g — the molar mass in grams, which is what a 1 molar solution means. For 1 L of 0.1 M it is 7.5067 g, and for 1 L of 0.01 M it is 0.75067 g.

How much for 100 mL of 0.1 M?

0.75067 g. The volume is a tenth of a litre and the strength a tenth of molar, so the mass is a hundredth of 75.067 g. In milligrams that is 750.67 mg.

Do I dissolve the solid first or make up the volume first?

Dissolve first, in perhaps 70% of the final volume, then make up to the mark. Adding solid to a full flask overshoots the volume and leaves the solution weak, and undissolved solid at the mark means the strength keeps changing as it goes in.

Can I dilute a stock solution instead of weighing?

Yes, and it is more accurate for small amounts. C₁V₁ = C₂V₂: to get 500 mL of 0.01 M from a 0.5 M stock, take 10 mL of stock and make up to 500 mL. Weighing the 375.33 mg that 500 mL of 0.01 M needs directly is the harder of the two.

Solution recipes for glycine

How the molar mass of glycine is arrived at
ElementAtomsAtomic weightContribution (g/mol)By mass
Oxygen (O)215.99931.99842.63%
Carbon (C)212.01124.02232%
Nitrogen (N)114.00714.00718.66%
Hydrogen (H)51.0085.046.714%
Total — one mole of glycine75.067100%

Standard atomic weights, IUPAC 2021. The contribution column is atoms × atomic weight, and the total is the molar mass this page uses: 75.067 g/mol.

Grams of glycine needed for a standard solution
Targetfor 100 mLfor 250 mLfor 500 mLfor 1 L
0.001 M7.5067 mg18.7667 mg37.5335 mg75.067 mg
0.005 M37.5335 mg93.8337 mg187.667 mg375.335 mg
0.01 M75.067 mg187.667 mg375.335 mg750.67 mg
0.05 M375.335 mg938.337 mg1.87667 g3.75335 g
0.1 M750.67 mg1.87667 g3.75335 g7.5067 g
0.15 M1.126 g2.81501 g5.63002 g11.26 g
0.2 M1.50134 g3.75335 g7.5067 g15.0134 g
0.25 M1.87667 g4.69169 g9.38337 g18.7667 g
0.5 M3.75335 g9.38337 g18.7667 g37.5335 g
1 M7.5067 g18.7667 g37.5335 g75.067 g
2 M15.0134 g37.5335 g75.067 g150.134 g

Each cell is molarity × volume in litres × 75.067 g/mol. Dissolve the solid first and then make up to the marked volume — adding solid to a full volume overshoots it.

Glycine among other organic compounds, by molar mass
CompoundFormulaMolar mass (g/mol)Millimoles in 1 g
UreaCH4N2O60.05616.651
Isopropyl alcoholC3H8O60.09616.64
Ethylene glycolC2H6O262.06816.111
Glycine (this page)C2H5NO275.06713.321
BenzeneC6H678.11412.802
GlycerolC3H8O392.09410.858
TolueneC7H892.14110.853

Ordered by molar mass. The last column is 1000/M, which is the number a weighed gram actually gives you.

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