Ethanol Solution Preparation

How many grams of ethanol to weigh for any molarity and volume, with a full recipe table.

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To prepare a solution of ethanol you need the grams, and grams is molarity × volume in litres × 46.069 g/mol. A litre of 1 M takes 46.069 g; 500 mL of 0.1 M takes 2.3035 g; 250 mL of 0.01 M takes 115.17 mg. Enter the strength you want and the volume you want it in, and the calculator returns the mass to weigh together with the same figure in milligrams and as a percentage strength.

The figure comes from the formula. Ethanol is 2 × 12.011 (C) + 6 × 1.008 (H) + 15.999 (O), which is 46.069 g/mol, taking standard atomic weights, and every page here computes that sum rather than quoting it. Carbon makes up the largest share of the mass: 2 of the 9 atoms in a formula unit are carbon, and they account for 24.022 g of the 46.069 g, or 52.14% by mass. The derivation table below breaks the whole molecule down element by element.

Order of operations matters more than precision here. Dissolve the solid in rather less than the final volume, then make up to the mark once it has all gone into solution and come back to room temperature — warm solutions read low when they cool. If the calculated mass is under about 20 mg, prepare ten times the strength and dilute it tenfold by pipette instead, because C₁V₁ = C₂V₂ carries less error than a marginal weighing.

Drinking alcohol and a solvent. Strength is quoted as percent by volume, and because ethanol is less dense than water that is not percent by weight. At 46.069 g/mol it is heavier than 1 of the 21 organic compounds covered here, and that ranking matters more than it looks: methanol has a molar mass of 32.042 g/mol, so a gram of it contains 43.8% more formula units than a gram of ethanol. Weigh by mass and you are not weighing equal amounts of substance.

Two practical things move the result. Purity below 100% means the weighed mass overstates how much compound you have — at 98% assay, 0.92138 g of every 46.069 g is not the compound — and any water picked up from the air does the same. Both are systematic, so they shift every solution made from that jar in the same direction.

The formula

m = c × (V ÷ 1000) × 46.069
c
The molarity you want, in mol/L
V
The volume you want to make, in millilitres
46.069
The molar mass of ethanol in g/mol, derived from its formula
m
The mass of ethanol to weigh out, in grams

How it works, step by step

  1. Enter the molarity you want, in mol/L.
  2. Enter the volume you want to make, in millilitres.
  3. The two are multiplied together and by 46.069 g/mol.
  4. The result is the mass to weigh; dissolve it in part of the volume and then make up to the mark.

Worked examples

250 mL of 0.1 M ethanol

Weigh 1.15173 g. That is 0.1 M × 0.25 L × 46.069 g/mol, and it comes to 1151.73 mg if your balance is set to milligrams. Dissolve in about 175 mL first, then make up to 250 mL.

500 mL of 0.5 M ethanol

Weigh 11.5173 g. That is 0.5 M × 0.5 L × 46.069 g/mol, and it comes to 11,517.2 mg if your balance is set to milligrams. Dissolve in about 350 mL first, then make up to 500 mL.

1000 mL of 1 M ethanol

Weigh 46.069 g. That is 1 M × 1 L × 46.069 g/mol, and it comes to 46,069 mg if your balance is set to milligrams. Dissolve in about 700 mL first, then make up to 1000 mL.

How to read your score

0–0NothingNothing to weigh.
0–0.05Below a sensible weighingUnder 50 mg. Weigh ten or a hundred times this and dilute; the balance error does not shrink with the sample.
0.05–10Weighable directlyFrom 50 mg to 10 g, which is where a two- or three-decimal balance gives better than 1% on the mass.
10–—Large batchMore than 10 g of ethanol. Worth checking solubility and, for a solid that generates heat on dissolving, adding it in portions.

Frequently asked questions

What is the molar mass of ethanol (C2H6O)?

It is 46.069 g/mol. That is the sum of the standard atomic weights of every atom in the formula: 2 × 12.011 (C) + 6 × 1.008 (H) + 15.999 (O). One mole of ethanol therefore weighs 46.069 g, and a gram of it is 21.707 mmol.

What percentage of ethanol is carbon?

52.14% by mass. Each formula unit contains 2 carbon atoms contributing 24.022 g of the 46.069 g total, so 100 g of ethanol contains 52.14 g of carbon and a kilogram contains 521.44 g of it.

How much ethanol do I need for 1 litre of 1 M solution?

46.069 g — the molar mass in grams, which is what a 1 molar solution means. For 1 L of 0.1 M it is 4.6069 g, and for 1 L of 0.01 M it is 0.46069 g.

How much for 100 mL of 0.1 M?

0.46069 g. The volume is a tenth of a litre and the strength a tenth of molar, so the mass is a hundredth of 46.069 g. In milligrams that is 460.69 mg.

Do I dissolve the solid first or make up the volume first?

Dissolve first, in perhaps 70% of the final volume, then make up to the mark. Adding solid to a full flask overshoots the volume and leaves the solution weak, and undissolved solid at the mark means the strength keeps changing as it goes in.

Can I dilute a stock solution instead of weighing?

Yes, and it is more accurate for small amounts. C₁V₁ = C₂V₂: to get 500 mL of 0.01 M from a 0.5 M stock, take 10 mL of stock and make up to 500 mL. Weighing the 230.35 mg that 500 mL of 0.01 M needs directly is the harder of the two.

Solution recipes for ethanol

How the molar mass of ethanol is arrived at
ElementAtomsAtomic weightContribution (g/mol)By mass
Carbon (C)212.01124.02252.14%
Oxygen (O)115.99915.99934.73%
Hydrogen (H)61.0086.04813.13%
Total — one mole of ethanol46.069100%

Standard atomic weights, IUPAC 2021. The contribution column is atoms × atomic weight, and the total is the molar mass this page uses: 46.069 g/mol.

Grams of ethanol needed for a standard solution
Targetfor 100 mLfor 250 mLfor 500 mLfor 1 L
0.001 M4.6069 mg11.5173 mg23.0345 mg46.069 mg
0.005 M23.0345 mg57.5863 mg115.173 mg230.345 mg
0.01 M46.069 mg115.173 mg230.345 mg460.69 mg
0.05 M230.345 mg575.863 mg1.15173 g2.30345 g
0.1 M460.69 mg1.15173 g2.30345 g4.6069 g
0.15 M691.035 mg1.72759 g3.45518 g6.91035 g
0.2 M921.38 mg2.30345 g4.6069 g9.2138 g
0.25 M1.15173 g2.87931 g5.75863 g11.5173 g
0.5 M2.30345 g5.75863 g11.5173 g23.0345 g
1 M4.6069 g11.5173 g23.0345 g46.069 g
2 M9.2138 g23.0345 g46.069 g92.138 g

Each cell is molarity × volume in litres × 46.069 g/mol. Dissolve the solid first and then make up to the marked volume — adding solid to a full volume overshoots it.

Ethanol among other organic compounds, by molar mass
CompoundFormulaMolar mass (g/mol)Millimoles in 1 g
MethanolCH4O32.04231.209
Ethanol (this page)C2H6O46.06921.707
AcetoneC3H6O58.0817.218
UreaCH4N2O60.05616.651
Isopropyl alcoholC3H8O60.09616.64
Ethylene glycolC2H6O262.06816.111
GlycineC2H5NO275.06713.321

Ordered by molar mass. The last column is 1000/M, which is the number a weighed gram actually gives you.

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